An SHM is given by $x = 5\sin(4\pi t + \pi/4)$ cm. The displacement at $t = 0.25$ s is:
- $5$ cm
- $2.5\sqrt 2$ cm
- $-5/\sqrt 2$ cm
- $-5$ cm
Show answer and solution
Correct answer: C. $-5/\sqrt 2$ cm
At $t = 0.25$: argument = $4\pi(0.25) + \pi/4 = \pi + \pi/4 = 5\pi/4$.
$\sin(5\pi/4) = -\sin(\pi/4) = -1/\sqrt 2$.
**So $x = 5 \times (-1/\sqrt 2) = -5/\sqrt 2$ cm.**