alleryAn SHM is given by $x = 5\sin(4\pi t + \pi/4)$ cm. The displacement at $t = 0.25$ s is:
A$5$ cm
B$2.5\sqrt 2$ cm
C$-5/\sqrt 2$ cm
D$-5$ cm
Answer & Solution
Correct answer: C. $-5/\sqrt 2$ cm
At $t = 0.25$: argument = $4\pi(0.25) + \pi/4 = \pi + \pi/4 = 5\pi/4$.
$\sin(5\pi/4) = -\sin(\pi/4) = -1/\sqrt 2$.
**So $x = 5 \times (-1/\sqrt 2) = -5/\sqrt 2$ cm.**
Keep practising Unit 1A: Kinematics: 1D Motion, Position & Velocity
Browse all Unit 1A: Kinematics: 1D Motion, Position & Velocity questions for AP Physics 1, or explore more Physics topics.
Related questions
The audible range of frequencies for a normal human ear is approximately:The loudness of a sound is related to its:The pitch of a sound is determined primarily by its:The maximum displacement of particles from their mean position is called the:If the frequency of a wave is f and its wavelength is λ, its speed v is given by:The time taken for one complete oscillation is the:The SI unit of frequency is the:The number of complete oscillations per second is called the: