The **rms speed** of gas molecules at absolute temperature $T$ is:
- $\sqrt{3RT/M_0}$ (also $\sqrt{3 k_B T/m}$)
- $\sqrt{2RT/M_0}$
- $RT/M_0$
- $3RT/M_0$
Show answer and solution
Correct answer: A. $\sqrt{3RT/M_0}$ (also $\sqrt{3 k_B T/m}$)
$v_{rms} = \sqrt{\overline{v^2}} = \sqrt{3RT/M_0} = \sqrt{3k_B T/m}$, where $M_0$ is molar mass, $m$ is molecular mass.