Start learning →

The **rms speed** of gas molecules at absolute temperature $T$ is:

A$\sqrt{3RT/M_0}$ (also $\sqrt{3 k_B T/m}$)
B$\sqrt{2RT/M_0}$
C$RT/M_0$
D$3RT/M_0$
Answer & Solution
Correct answer: A. $\sqrt{3RT/M_0}$ (also $\sqrt{3 k_B T/m}$)
$v_{rms} = \sqrt{\overline{v^2}} = \sqrt{3RT/M_0} = \sqrt{3k_B T/m}$, where $M_0$ is molar mass, $m$ is molecular mass.
Practise this question with Quill — Karnataka PUC I →

Keep practising Kinetic Theory & Oscillations

Browse all Kinetic Theory & Oscillations questions for Karnataka PUC I, or explore more Physics topics.

Start a Kinetic Theory & Oscillations lesson →