The **law of equipartition of energy** states that, at temperature $T$, each quadratic degree of freedom contributes:
- $k_B T$
- $\frac{1}{2} k_B T$
- $\frac{3}{2} k_B T$
- $RT$
Show answer and solution
Correct answer: B. $\frac{1}{2} k_B T$
Each independent quadratic term in the energy expression (translational, rotational, vibrational kinetic + potential) contributes $\frac{1}{2} k_B T$ to the average energy.