alleryThe ratio of average KE of a monatomic gas to that of a rigid diatomic gas, at the **same T**, is:
A3:5 (monatomic 3 DOF, diatomic 5 DOF, all × ½ k_BT)
B1:1
C5:3
DCannot be determined
Answer & Solution
Correct answer: A. 3:5 (monatomic 3 DOF, diatomic 5 DOF, all × ½ k_BT)
Average energy per molecule = (DOF/2) k_B T. Monatomic: (3/2) k_B T. Diatomic rigid: (5/2) k_B T. Ratio = 3:5.
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