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Bihar Board Class 10 (BSEB) Intro Trigonometry — practice questions

Explore 19 free Intro Trigonometry questions in Bihar Board Class 10 (BSEB) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Intro Trigonometry questions and exercises with answers

Showing questions 1–19 of 19.

In a right triangle with respect to acute angle A, sin A is defined as:Read the answer and worked solution →In a right triangle, if sin A = 3/5, what is cosec A?Read the answer and worked solution →In a right triangle with hypotenuse 13 and opposite (to A) = 5, what is cos A?Read the answer and worked solution →If tan A = 4/3, find sin A.Read the answer and worked solution →In a right triangle, cos A · sec A equals:Read the answer and worked solution →Evaluate sin 30° + cos 60°.Read the answer and worked solution →Find tan 45° + cot 45°.Read the answer and worked solution →Evaluate cos 60° · sin 30° + sin 60° · cos 30°.Read the answer and worked solution →sin 67° equals which of the following (using complementary angles)?Read the answer and worked solution →Compute sin 60° · cos 30° − cos 60° · sin 30°.Read the answer and worked solution →Find tan 30° · tan 60°.Read the answer and worked solution →If sin A = 1/2, find cos²A.Read the answer and worked solution →Simplify sec²θ − tan²θ.Read the answer and worked solution →Simplify (1 − cos²θ) / sin²θ for sin θ ≠ 0.Read the answer and worked solution →If sec A = 5/3, find tan A.Read the answer and worked solution →Simplify (sin A + cos A)² + (sin A − cos A)².Read the answer and worked solution →Prove or evaluate: (1 + tan²A)(1 − sin²A).Read the answer and worked solution →Match each trigonometric ratioRead the answer and worked solution →Which value is larger?Read the answer and worked solution →

Worked practice questions

In a right triangle with respect to acute angle A, sin A is defined as:

  1. opposite / hypotenuse
  2. adjacent / opposite
  3. adjacent / hypotenuse
  4. opposite / adjacent
Show answer and solution

Correct answer: A. opposite / hypotenuse

sin A = opposite side / hypotenuse, by definition.

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In a right triangle, if sin A = 3/5, what is cosec A?

  1. 4/5
  2. 5/3
  3. 3/5
  4. 5/4
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Correct answer: B. 5/3

We have cosec A = 1/sin. So A = 5/3.

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In a right triangle with hypotenuse 13 and opposite (to A) = 5, what is cos A?

  1. 12/13
  2. 13/12
  3. 5/12
  4. 5/13
Show answer and solution

Correct answer: A. 12/13

Adjacent² = 13² − 5² = 169 − 25 = 144, so adjacent = 12. cos A = adjacent/hypotenuse = 12/13.

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