If sec A = 5/3, find tan A.
A4/3
B3/5
C3/4
D2/3
Answer & Solution
Correct answer: A. 4/3
1 + tan²A = sec²A = 25/9. So tan²A = 25/9 − 1 = 16/9, hence tan A = 4/3 (positive for acute A).
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