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Assam CEE Organic Chemistry — practice questions

Explore 66 free Organic Chemistry questions in Assam CEE Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Organic Chemistry questions and exercises with answers

Showing questions 1–30 of 66.

Hydrocarbons are organic compounds composed exclusively of:Read the answer and worked solution →In the presence of organic peroxides, addition of HBr to propene gives predominantly:Read the answer and worked solution →Wurtz reaction is used to prepare:Read the answer and worked solution →According to VSEPR theory, the shape of a molecule is determined byRead the answer and worked solution →The hybridisation of carbon in methane (CH₄) isRead the answer and worked solution →Which molecule is non-polar despite having polar bonds?Read the answer and worked solution →The bond order of the oxygen molecule O₂ (by molecular orbital theory) isRead the answer and worked solution →A coordinate (dative) bond differs from a normal covalent bond in thatRead the answer and worked solution →Which species has sp hybridisation on the central atom?Read the answer and worked solution →As bond order increases, bond lengthRead the answer and worked solution →An ionic bond forms byRead the answer and worked solution →The shape of NH₃ is pyramidal rather than planar becauseRead the answer and worked solution →Which has the highest dipole moment?Read the answer and worked solution →Among the following, which is paramagnetic?Read the answer and worked solution →Formal charge on an atom =Read the answer and worked solution →Line up three from one blockRead the answer and worked solution →Order the atomic models as they were proposedRead the answer and worked solution →Match each scientist to their modelRead the answer and worked solution →Match each model to what it could NOT explainRead the answer and worked solution →True or false: Rutherford's modelRead the answer and worked solution →True or false: Bohr's modelRead the answer and worked solution →Complete the reason Bohr's model failsRead the answer and worked solution →Which model does this belong to?Read the answer and worked solution →Match each quantum number to what it is calledRead the answer and worked solution →True or false: the quantum mechanical modelRead the answer and worked solution →Order the structure: from atom down to electronRead the answer and worked solution →Complete the (n + l) ruleRead the answer and worked solution →True or false: orbital energiesRead the answer and worked solution →Match each rule to what it forbids or requiresRead the answer and worked solution →Tap every statement Hund's rule requiresRead the answer and worked solution →

Worked practice questions

Hydrocarbons are organic compounds composed exclusively of:

  1. Carbon and oxygen
  2. Carbon and hydrogen
  3. Carbon and nitrogen
  4. Hydrogen and nitrogen
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Correct answer: B. Carbon and hydrogen

By definition, hydrocarbons contain **only** carbon and hydrogen atoms. Adding oxygen, nitrogen, halogens, etc. produces other functional-group families (alcohols, amines, halides). Three main classes: - **Alkanes**: only single C-C bonds, $C_nH_{2n+2}$. - **Alkenes**: contain at least one C=C double bond, $C_nH_{2n}$. - **Alkynes**: contain at least one C≡C triple bond, $C_nH_{2n-2}$. Aromatic hydrocarbons (e.g. benzene) are a special case.

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In the presence of organic peroxides, addition of HBr to propene gives predominantly:

  1. 1-bromopropane (anti-Markovnikov)
  2. propan-1-ol
  3. 2-bromopropane (Markovnikov)
  4. propane
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Correct answer: A. 1-bromopropane (anti-Markovnikov)

Kharasch peroxide effect: HBr in the presence of organic peroxides (e.g. benzoyl peroxide) adds **anti-Markovnikov** via a free-radical mechanism. Br ends up on the **less** substituted carbon. Product: 1-bromopropane. Why: the radical chain involves a Br• radical adding to the alkene first. Br• prefers the less-substituted carbon, forming the more stable carbon radical. Then HBr donates H• to complete the addition. Notably, the peroxide effect is **specific to HBr**. HCl and HI don't show it.

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Wurtz reaction is used to prepare:

  1. Alkenes from alkyl halides
  2. Symmetric alkanes from alkyl halides
  3. Alcohols from alkanes
  4. Carboxylic acids from alkanes
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Correct answer: B. Symmetric alkanes from alkyl halides

**Wurtz reaction**: $2 R X + 2 Na \xrightarrow{\text{dry ether}} R{-}R + 2 NaX$. Two alkyl halide molecules combine, with sodium metal as the reducing agent, to give a higher symmetric alkane with double the carbon chain. Example: $\mathrm{CH_3 I + CH_3 I \xrightarrow{2Na} CH_3 CH_3}$ (ethane). Limitation: doesn't work well for asymmetric alkanes — mixing two different RX gives a statistical mixture of R-R, R'-R' and R-R', hard to separate. So Wurtz is best for symmetric products.

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