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Assam CEE Concentration Units — practice questions

Explore 1 free Concentration Units questions in Assam CEE Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Concentration Units questions and exercises with answers

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If 18 g of glucose (M = 180 g/mol) is dissolved in 90 g of water (M = 18 g/mol), the mole fraction of glucose is approximately:Read the answer and worked solution →

Worked practice questions

If 18 g of glucose (M = 180 g/mol) is dissolved in 90 g of water (M = 18 g/mol), the mole fraction of glucose is approximately:

  1. 0.020
  2. 0.50
  3. 0.050
  4. 0.10
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Correct answer: A. 0.020

$n_{glucose} = 18/180 = 0.10$ mol; $n_{water} = 90/18 = 5.0$ mol. $x_{glucose} = 0.10/(0.10 + 5.0) = 0.10/5.10 \approx 0.0196 \approx 0.020$.

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