alleryIf 18 g of glucose (M = 180 g/mol) is dissolved in 90 g of water (M = 18 g/mol), the mole fraction of glucose is approximately:
A0.020
B0.50
C0.050
D0.10
Answer & Solution
Correct answer: A. 0.020
$n_{glucose} = 18/180 = 0.10$ mol; $n_{water} = 90/18 = 5.0$ mol.
$x_{glucose} = 0.10/(0.10 + 5.0) = 0.10/5.10 \approx 0.0196 \approx 0.020$.
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