The HEXACYANIDOFERRATE(II) ion $[\mathrm{Fe(CN)_6}]^{4-}$ contains iron in oxidation state
- $+1$
- $+2$
- $+3$
- $+4$
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Correct answer: B. $+2$
1. The hexacyanidoferrate(II) IUPAC suffix '-(II)' explicitly tells us the iron oxidation state — but let's compute it as a check.
2. Total charge on the complex ion: $-4$.
3. Six $\mathrm{CN^-}$ ligands contribute $-6$ total charge.
4. Let Fe oxidation state be $x$: $x + 6(-1) = -4 \Rightarrow x = +2$.
5. So iron is in the $+2$ state, consistent with the (II) in the name.
6. This ion forms the famous ferrocyanide salts — yellow prussiate of potash, $K_4[\mathrm{Fe(CN)_6}]$.
7. Options A, C, D would all require a different complex charge.
_Source: syllabus Chemistry Part 1, Ch 5, §5.3 (Oxidation state calculation + nomenclature consistency), p. 4–5._