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ACSEE (Form 6) Aliphatic Hydrocarbons — practice questions

Explore 9 free Aliphatic Hydrocarbons questions in ACSEE (Form 6) Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Aliphatic Hydrocarbons questions and exercises with answers

Showing questions 1–9 of 9.

Worked practice questions

The general combustion equation for a hydrocarbon $C_xH_y$ requires how many moles of oxygen?

  1. $x+\dfrac{y}{4}$
  2. $x+\dfrac{y}{2}$
  3. $2x+\dfrac{y}{4}$
  4. $\dfrac{x}{4}+y$
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Correct answer: A. $x+\dfrac{y}{4}$

1. Complete combustion gives carbon dioxide and water: $C_xH_y+O_2\rightarrow xCO_2+\dfrac{y}{2}H_2O$. 2. Balance the carbon first: $x$ carbons give $x$ molecules of $CO_2$, needing $x$ molecules of $O_2$. 3. Balance the hydrogen: $y$ hydrogens give $\dfrac{y}{2}$ molecules of water, which carry $\dfrac{y}{2}$ oxygen atoms. 4. Those $\dfrac{y}{2}$ atoms come from $\dfrac{y}{4}$ molecules of $O_2$. 5. Adding the two requirements gives $\left(x+\dfrac{y}{4}\right)$ moles of oxygen. _Source: NECTA ACSEE 2024 Chemistry 132/1, Question 1: Aliphatic Hydrocarbons_

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20 cm³ of a hydrocarbon burnt in excess oxygen leaves 100 cm³, of which KOH absorbs 60 cm³. The number of carbon atoms is:

  1. 3
  2. 2
  3. 4
  4. 6
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Correct answer: A. 3

1. Concentrated potassium hydroxide absorbs carbon dioxide, so the 60 cm³ removed is the $CO_2$ produced. 2. At the same temperature and pressure, gas volumes are in the same ratio as moles. 3. So 20 cm³ of hydrocarbon produced 60 cm³ of carbon dioxide. 4. That is a ratio of 1 to 3, meaning each molecule yields 3 molecules of $CO_2$. 5. Each carbon atom becomes one $CO_2$, so the hydrocarbon has 3 carbon atoms. _Source: NECTA ACSEE 2024 Chemistry 132/1, Question 1: Aliphatic Hydrocarbons_

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Which reaction type?

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Items
  1. Group
    Addition
    Item
    Adds to C=C
  2. Group
    Addition
    Item
    Nothing leaves
  3. Group
    Substitution
    Item
    Group swapped
  4. Group
    Substitution
    Item
    Has a leaver
  5. Group
    Elimination
    Item
    Two groups go
  6. Group
    Elimination
    Item
    Makes a C=C
Groups
  1. Item
    Addition
  2. Item
    Substitution
  3. Item
    Elimination
Instructions
Steer each description into the reaction type it defines.

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