ACSEE (Form 6) Statistics — practice questions
5 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice ACSEE (Form 6) Statistics in the app →For 36 stones with assumed mean $A=225$, $ um fd=-750$ and $ um fd^2=197500$, the mean by the deviation methodWith $N=36$, $ um fd^2=197500$ and $ um fd=-750$, the variance of the distribution to three decimal places is:A grouped distribution of 36 stones has quartile class lower boundary $L=150$, $n_b=8$, $n_w=10$ and class widWith $N=36$, $L=300$, $n_b=32$, $n_w=4$ and $c=50$, the 90th percentile of the distribution is:For grouped data with $L=39.5$, $N=180$, $f_b=37$, $n_w=73$ and $c=10$, the lower quartile is: