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Accuplacer Radical and Absolute Value Equations — practice questions

Explore 4 free Radical and Absolute Value Equations questions in Accuplacer Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Radical and Absolute Value Equations questions and exercises with answers

Showing questions 1–4 of 4.

Worked practice questions

In a rational exponent, what does the denominator of the fraction stand for?

  1. A root of the base
  2. A power of the base
  3. A factor of the base
  4. A multiple of the base
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Correct answer: A. A root of the base

1. A rational exponent is a fraction written where an exponent would go. 2. The numerator of that fraction gives the power applied to the base. 3. The denominator gives the root taken of the base, so a denominator of 2 means a square root. _Source: OpenStax College Algebra (CC BY 4.0), section 2.6 Other Types of Equations_

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How many solutions does the equation the absolute value of (3x + 4) equal to negative 9 have?

  1. It has one solution
  2. It has two solutions
  3. It has no solution
  4. It has three solutions
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Correct answer: C. It has no solution

1. An absolute value measures a distance, so it can never come out negative. 2. The right side here is negative 9, which no distance can equal. 3. So the equation has no solution at all. 4. Had the right side been positive there would have been two solutions, and zero would have given one. _Source: OpenStax College Algebra (CC BY 4.0), section 2.6 Other Types of Equations_

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Solve the radical equation the square root of (x + 6) equal to x.

  1. Only x = -2 works
  2. Both 3 and -2 work
  3. Neither value works
  4. Only x = 3 works
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Correct answer: D. Only x = 3 works

1. The radical is already alone on the left, so square both sides. 2. Squaring gives x plus 6 equal to x squared. 3. Rearranging gives x squared minus x minus 6 equal to 0. 4. Factoring gives the brackets (x minus 3) and (x plus 2). 5. So the proposed solutions are x equal to 3 and x equal to negative 2. 6. Test x equal to 3: the square root of 9 is 3, which matches the right side. 7. Test x equal to negative 2: the square root of 4 is 2, but the right side is negative 2, so it fails. 8. Squaring both sides created that second root, so it is extraneous and only x equal to 3 survives. 9. Keeping both values skips the check that squaring makes necessary. 10. Rejecting both values ignores that x equal to 3 does satisfy the original equation. _Source: OpenStax College Algebra (CC BY 4.0), section 2.6 Other Types of Equations_

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