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5 km/h ବେଗରେ ଚାଲୁଥିବା ଜଣେ ବାଳକ 6 minutes ବିଳମ୍ବରେ ପହଞ୍ଚେ, କିନ୍ତୁ 6 km/h ବେଗରେ ସେ 6 minutes ପୂର୍ବରୁ ପହଞ୍ଚେ। ତାହାର ଗନ୍ତବ୍ୟସ୍ଥଳ କେତେ ଦୂର?

A4 km
B6 km
C8 km
D5 km
Answer & Solution
Correct answer: B. 6 km
d/5 - d/6 = 12 min = 0.2 h ରୁ ମିଳେ d/30 = 0.2, ତେଣୁ d = 6 km।
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