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A motor wheel goes from 1200 rpm to 3120 rpm uniformly in 16 s. What is its angular acceleration?
A120 rad/s^2
B2π rad/s^2
C8π rad/s^2
D4π rad/s^2
Answer & Solution
Correct answer: D. 4π rad/s^2
Δω = 1920 rpm = 1920 x 2π/60 = 64π rad/s; dividing by 16 s gives 4π rad/s^2.
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