Home › CBSE Class 11 (Science) › Physics › Rotational Motion › A 10 N force acts 0.5 m from a pivot at 30 degre…
A 10 N force acts 0.5 m from a pivot at 30 degrees to the position vector. Find the torque.
A1.25 N m
B2.5 N m
C5 N m
D4.3 N m
Answer & Solution
Correct answer: B. 2.5 N m
Torque = rF sin 30 degrees = 0.5 x 10 x 0.5 = 2.5 N m.
Related questions
Which property is shared by both the scalar and the vector product?Moment of force and angular momentum are both defined asA wheel turns through angle Δθ in time Δt. Its average angular velocity isThe moment of inertia of a composite rigid system about an axis isMoment of inertia about an axis equals the ratio of the applied torque to the resultingTwo small masses m are fixed at the ends of a light rod of length l. I about a perpendiculThe total torque on a system does not depend on the chosen origin when the total externalA rigid body fixed at one point or along a line can have