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A rod of mass 3 kg, length 2 m, spins about a perpendicular axis at its midpoint. Its I is
A0.5 kg m^2
B2 kg m^2
C1 kg m^2
D4 kg m^2
Answer & Solution
Correct answer: C. 1 kg m^2
I = ML^2/12 = 3 x 4 / 12 = 1 kg m^2 for a rod about its perpendicular bisector.
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