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A ring of mass 2 kg, radius 0.5 m, spins about its central perpendicular axis. Its I is
A0.125 kg m^2
B1.0 kg m^2
C0.5 kg m^2
D0.25 kg m^2
Answer & Solution
Correct answer: C. 0.5 kg m^2
For a ring about its central perpendicular axis I = MR^2 = 2 x 0.25 = 0.5 kg m^2.
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