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2-Bromopentane with alcoholic KOH gives which major product?

APent-1-ene
BPentan-2-ol
CPent-1-yne
DPent-2-ene
Answer & Solution
Correct answer: D. Pent-2-ene
Pent-2-ene is the more substituted alkene, so Zaitsev's rule makes it the major product.
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