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(-)-2-Bromooctane reacts with NaOH by SN2. What is the product?
A(+)-Octan-2-ol
B(-)-Octan-2-ol
C(±)-Octan-2-ol
DOct-1-ene only
Answer & Solution
Correct answer: A. (+)-Octan-2-ol
SN2 inverts the configuration, and the alcohol formed is (+)-octan-2-ol.
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