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A reaction has dG0 = +13.8 kJ/mol at 298 K. Its Kc is about
A2.62 x 10^2
B3.81 x 10^-3
C5.57 x 10^0
D1.00 x 10^0
Answer & Solution
Correct answer: B. 3.81 x 10^-3
ln K = -13800 / (8.314 x 298) = -5.57, so K = e^-5.57, about 3.81 x 10^-3.
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