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Which relation connects Kp and Kc for a gaseous equilibrium?
AKp = Kc + RT(dn)
BKp = Kc(RT)^-dn
CKp = Kc / (RT)
DKp = Kc(RT)^dn
Answer & Solution
Correct answer: D. Kp = Kc(RT)^dn
Since p = cRT for each gas, Kp = Kc(RT) raised to the change in gaseous moles.
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