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From F = Gm1m2/r², the dimensions of G are?
A[M⁻¹ L² T⁻²]
B[M L³ T⁻²]
C[M⁻¹ L³ T⁻²]
D[M⁻² L³ T⁻¹]
Answer & Solution
Correct answer: C. [M⁻¹ L³ T⁻²]
From F = Gm1m2/r², G = Fr²/m², which gives [M L T⁻²][L²][M⁻²] = [M⁻¹ L³ T⁻²].
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