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For a first order reaction, 99.9% completion takes about how many half-lives?

A10 half-lives
B2 half-lives
C8 half-lives
D5 half-lives
Answer & Solution
Correct answer: A. 10 half-lives
t(99.9%) = (2.303/k) log 1000 = 6.909/k, which is about 10 times 0.693/k.
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