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H2S has a solubility of 0.195 m in water at STP (0.987 bar). Taking 55.5 mol water per kg, what is its Henry's law constant?
A2820 bar
B282 bar
C28.2 bar
D0.282 bar
Answer & Solution
Correct answer: B. 282 bar
x = 0.195/(55.5 + 0.195) = 3.50 × 10^-3, so KH = 0.987/0.00350 = 282 bar.
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