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Assuming complete dissociation, what is the freezing point depression of 0.10 m aqueous NaCl? (Kf = 1.86 K kg/mol)
A0.093 K
B0.372 K
C0.558 K
D0.186 K
Answer & Solution
Correct answer: B. 0.372 K
With i = 2, the depression is 2 × 1.86 × 0.10 = 0.372 K.
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