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62 g ethylene glycol (62 g/mol) in 500 g water, Kf = 1.86. Freezing point?
A269.43 K
B270.30 K
C271.29 K
D276.87 K
Answer & Solution
Correct answer: A. 269.43 K
1 mol in 0.5 kg is 2 m, so the depression is 1.86 × 2 = 3.72 K and 273.15 - 3.72 = 269.43 K.
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