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2.0 g solute in 100 g benzene (Kb 2.53) raises bp by 0.506 K. Molar mass?
A100 g/mol
B25 g/mol
C50 g/mol
D200 g/mol
Answer & Solution
Correct answer: A. 100 g/mol
M = (2.53 × 2.0 × 1000)/(0.506 × 100) = 5060/50.6 = 100 g/mol.
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