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For the same metal, ligands and distances, how does Δt compare with Δo?

AΔt = (2/3)Δo
BΔt = (4/9)Δo
CΔt = (3/5)Δo
DΔt = (9/4)Δo
Answer & Solution
Correct answer: B. Δt = (4/9)Δo
Tetrahedral splitting is smaller than octahedral splitting, with Δt equal to four-ninths of Δo.
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