Home › CBSE Class 11 (Science) › Chemistry › Hydrocarbons › For dehydrohalogenation with alcoholic KOH, the …
For dehydrohalogenation with alcoholic KOH, the halogen order is:
ACl > Br > I
BCl > I > Br
CI > Br > Cl
DBr > I > Cl
Answer & Solution
Correct answer: C. I > Br > Cl
The weakest carbon-halogen bond, C-I, breaks fastest, so iodides react first.
Related questions
In naming an alkyne, the parent chain must:Excess bromine adds to an alkyne to finally give a:Small cyclic alkynes are rare mainly because:The general formula of open-chain alkynes with one triple bond is:Natural rubber is a polymer of:When irradiated with UV light, alkenes dimerise to give:Industrial epoxidation of ethylene with oxygen uses a catalyst based on:Which of these groups contains a carbon-carbon double bond?