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A molecule of mass m and x-velocity vx rebounds elastically off a wall. Momentum change?
A2m vx
Bm vx
Czero
D4m vx
Answer & Solution
Correct answer: A. 2m vx
The x-component reverses from +vx to -vx, so the momentum changes by m vx - (-m vx) = 2m vx.
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