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Why do transition metals form so many complexes?
ALarge ions, high charge, no d orbitals
BSmall ions, low charge, full s orbitals
CLarge ions, low charge, full d orbitals
DSmall ions, high charge, free d orbitals
Answer & Solution
Correct answer: D. Small ions, high charge, free d orbitals
Small size, high ionic charge and available d orbitals let these ions bind many ligands.
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