Where one mole of gas occupies 22.7 L, 22.7 L of methane burns completely in how much oxygen?
A22.7 L
B45.4 L
C11.35 L
D68.1 L
Answer & Solution
Correct answer: B. 45.4 L
One mole of methane needs two moles of oxygen, so 22.7 L of methane needs 2 x 22.7 = 45.4 L.
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