For H2(g) + Cl2(g) → 2HCl(g), how do ∆H and ∆U compare?
A∆H is less by 2RT
B∆H exceeds ∆U by RT
C∆H exceeds ∆U by 2RT
D∆H is equal to ∆U
Answer & Solution
Correct answer: D. ∆H is equal to ∆U
Two moles of gas give two moles of gas, so ∆ng = 0 and the ∆ngRT term vanishes.
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