For isothermal reversible expansion of n mol of ideal gas, the work w equals:
A-2.303 nRT log(Vf/Vi)
B-2.303 nRT log(Vi/Vf)
C+2.303 nRT log(Vf/Vi)
D-nR log(Vf/Vi)
Answer & Solution
Correct answer: A. -2.303 nRT log(Vf/Vi)
Integrating -p dV with p = nRT/V gives w = -nRT ln(Vf/Vi), which is negative for expansion.
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