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ꯃꯊꯪꯒꯤ ꯋꯥꯐꯃꯁꯤꯡ ꯊꯤꯕꯤꯌꯨ: 3, 7, 15, 31, 63, ?

A125
B99
C127
D95
Answer & Solution
Correct answer: C. 127
ꯇꯔꯝ ꯈꯨꯗꯤꯡꯃꯛ 2 × ꯃꯃꯥꯡꯒꯤ + 1: 3 → 7 (2×3+1), 7 → 15 (2×7+1), 15 → 31, 31 → 63, 63 → 127.ꯅꯠꯔꯒꯥ 2−+1 - 1.
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