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આગળનું પદ શોધો: 3, 7, 15, 31, 63, ?

A125
B99
C127
D95
Answer & Solution
Correct answer: C. 127
દરેક પદ 2 × અગાઉનું પદ + 1 છે: 3 → 7 (2×3+1), 7 → 15 (2×7+1), 15 → 31, 31 → 63, 63 → 127. અથવા 2ⁿ⁺¹ - 1.
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