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$6$ ಸೆಂ.ಮೀ. ಬದಿ ಇರುವ ಸಮಬಾಹು ತ್ರಿಭುಜದ ವಿಸ್ತೀರ್ಣವನ್ನು ಕಂಡುಹಿಡಿಯಿರಿ.

A$6\sqrt{3}$ cm²
B$9\sqrt{3}$ cm²
C$12\sqrt{3}$ cm²
D$18$ cm²
Answer & Solution
Correct answer: B. $9\sqrt{3}$ cm²
ಸಮಬಾಹು ತ್ರಿಭುಜದ ವಿಸ್ತೀರ್ಣ $= \dfrac{\sqrt{3}}{4} \times \text{side}^2 = \dfrac{\sqrt{3}}{4} \times 36 = 9\sqrt{3}$ cm².
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