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Using alternating digit sums, which number is divisible by 11?

A122
B123
C121
D124
Answer & Solution
Correct answer: C. 121
1. Alternating sum of 121 is 1 - 2 + 1 = 0, which is divisible by 11. 2. The others give 1, 2 and 3, none divisible by 11. 3. So 121 (= 11 x 11) is the answer. _Source: Wikipedia, Divisibility rule, section Divisibility by 11_
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