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Brown eyes (B) is dominant over blue (b). Bb father × bb mother. Probability of blue-eyed child:
A3/4
B0
C1/4
D1/2 (Bb × bb → 1/2 Bb (brown) : 1/2 bb (blue))
Answer & Solution
Correct answer: D. 1/2 (Bb × bb → 1/2 Bb (brown) : 1/2 bb (blue))
Bb × bb: father gives B (50%) or b (50%); mother always gives b. Offspring: 50% Bb (brown), 50% bb (blue). P(blue) = 1/2.
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