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**Time and Work — formulas used here.** - Work done in unit time. If a worker finishes a job in $m$ days, the fraction of work done in one day is $\tfrac{1}{m}$. - Combined work (two workers). A finishes in $X$ days, B in $Y$ days; together they finish in $\tfrac{XY}{X+Y}$ days. - Combined work (three workers). A, B, C take $X$, $Y$, $Z$ days; together they take $\tfrac{XYZ}{XY+YZ+ZX}$ days. - Efficiency–time inverse. If A is $k$ times as efficient as B, A takes $\tfrac{1}{k}$ as long. - Workforce equivalence. $M_1 D_1 T_1 = M_2 D_2 T_2$ for the same work, where $M$ = workers, $D$ = days, $T$ = hours/day. **Question.** If A can finish a piece of work in 12 days, what fraction of the work does A finish in a single day?
A$\dfrac{1}{6}$
B$\dfrac{1}{8}$
C$\dfrac{1}{12}$
D$\dfrac{1}{24}$
Answer & Solution
Correct answer: C. $\dfrac{1}{12}$
Directly applying the unit-rate rule: if a worker finishes a job in $m$ days, one day's work is $\tfrac{1}{m}$. For $m = 12$, that is $\tfrac{1}{12}$.
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