Apparent depth of object at real depth d in water (n = 4/3) seen from above is:
Ad
Bd × n
Cd × n²
Dd/n = 3d/4 (object appears shallower)
Answer & Solution
Correct answer: D. d/n = 3d/4 (object appears shallower)
Light from object refracts when leaving water; image position shifts. For viewing perpendicular: apparent depth = real depth / n. A 1 m deep pool appears 75 cm deep when viewed from above.
Related questions
Light passes from air to glass ($n = 1.5$). Brewster's angle is:Polaroid sunglasses reduce glare from a wet road most effectively because:In single-slit diffraction with $\lambda = 500$ nm and slit width $a = 0.1$ mm, the angulaIn Young's double slit, $\lambda = 600$ nm, slit separation $d = 0.5$ mm, screen distance For thin lens, when image distance equals object distance (|v| = |u|), object position is:Diffraction effects are more noticeable when the obstacle/aperture size is:Speed of light in glass (n = 1.5) is approximately:Refractive index of medium 1 with respect to medium 2 (denoted ₁n₂ or n₁/n₂). If ₁n₂ = 1.5