Apparent depth of object at real depth d in water (n = 4/3) seen from above is:
Ad
Bd × n
Cd × n²
Dd/n = 3d/4 (object appears shallower)
Answer & Solution
Correct answer: D. d/n = 3d/4 (object appears shallower)
Light from object refracts when leaving water; image position shifts.
**For viewing perpendicular:** apparent depth = real depth / n.
A 1 m deep pool appears 75 cm deep when viewed from above.
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