Home › UP Board Class 12 › physics › Wave Optics › In Young's double slit, $\lambda = 600$ nm, slit…
In Young's double slit, $\lambda = 600$ nm, slit separation $d = 0.5$ mm, screen distance $D = 1$ m. Fringe width is:
A$0.3$ mm, ignoring the slit separation in the formula here
B$1.2$ mm, by $\beta = \lambda D/d$ with the given values
C$3$ mm, since fringe width scales with $\lambda D \cdot d$ here
DZero, since coherent slits give a single bright point only
Answer & Solution
Correct answer: B. $1.2$ mm, by $\beta = \lambda D/d$ with the given values
$\beta = \lambda D/d = 600\times 10^{-9}\cdot 1/0.5\times 10^{-3} = 1.2\times 10^{-3}$ m = 1.2 mm.
Related questions
Newton originally supported the corpuscular theory of light. The wave theory was strongly In a Young's double-slit experiment, a thin transparent sheet of thickness t and refractivCoherent sources are those that emit waves ofIf polarised light of intensity I passes through a polariser whose axis makes angle θ withAn unpolarised light of intensity I₀ passes through a polariser. The transmitted intensityWhich of the following phenomena is characteristic ONLY of transverse waves and NOT of lonThe polarising angle (Brewster angle) for glass of refractive index 1.5 isThe width of the central maximum in single-slit diffraction on a screen at distance D is