In single-slit diffraction with $\lambda = 500$ nm and slit width $a =…

Question

In single-slit diffraction with $\lambda = 500$ nm and slit width $a = 0.1$ mm, the angular position of the first minimum is approximately:

Accepted Answer

D. $5	imes 10^{-3}$ rad, since $\sin	heta \approx \lambda/a$

$\sin	heta \approx \lambda/a = 500	imes 10^{-9}/10^{-4} = 5	imes 10^{-3}$ rad.

Answer

$0.5$ rad, ignoring the slit width entirely here

Answer

$0$ rad, since the central maximum has no edge value

Answer

$0.05$ rad, by simple ratio without the lambda value