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For the single-slit diffraction pattern shown, the angular position of the FIRST minimum from central maximum is θ₁ where: ![diagram](https://qallery.app/diagrams/v2_jee_optics_seed_2/img-8.jpeg)

Aa sin θ₁ = λ/2
Ba sin θ₁ = λ (slit width a)
CNo minimum exists
Da sin θ₁ = 2λ
Answer & Solution
Correct answer: B. a sin θ₁ = λ (slit width a)
Single-slit minima: a sin θ = mλ (m = ±1, ±2, ...). First minimum at sin θ = λ/a. Central maximum width = 2λ/a (between first minima on either side). Wider than YDSE fringes.
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