Inverse image f⁻¹(B) under f: X → Y for B ⊆ Y:

ASame as image

B∅

D{x ∈ X : f(x) ∈ B} (preimage of set B)

Answer & Solution

Correct answer: D. {x ∈ X : f(x) ∈ B} (preimage of set B)

f⁻¹(B) = preimage = {x ∈ X : f(x) ∈ B}. Defined even if f is not bijection (returns subset, not single element). E.g., for f(x) = x², f⁻¹({4}) = {-2, 2}.

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