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100 students; 50 like math, 60 like physics, 30 like both. Find students who like neither:
A30
B40
C0
D20 (= 100 - n(M ∪ P) = 100 - (50+60-30) = 100-80 = 20)
Answer & Solution
Correct answer: D. 20 (= 100 - n(M ∪ P) = 100 - (50+60-30) = 100-80 = 20)
n(M ∪ P) = 50 + 60 - 30 = 80 like at least one. Neither = 100 - 80 = 20.
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