Finkelstein reaction:
ARandom
BRX + NaOH
CR-X + Mg
DR-Br + NaI → RI + NaBr (in acetone, conversion to iodide)
Answer & Solution
Correct answer: D. R-Br + NaI → RI + NaBr (in acetone, conversion to iodide)
Finkelstein: R-Br + NaI (in acetone) → R-I + NaBr↓. NaBr insoluble in acetone, precipitates out, driving equilibrium toward R-I. Converts alkyl chlorides/bromides to iodides (often easier to react).
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